Chemistry - Complete P-block Question with Solution | TestHub
ChemistryComplete P-blockp-Block 15,16Hard2 minQB
ChemistryHardinteger
Consider the following reactions and information. Give your answer for the product(s) in which the underlined atom (on the reactant side) is present, and find (p + q + r + s) :
(a) H₂O₂ oxidises Fe²⁺ to product P1 (acidic medium) ; magnitude of the oxidation number of Fe in P1 = p
(b) B₂H₆ + CO → P2 ; number of σ bonds in one molecule of P2 = q
(c) CaC₂ + H₂O → P3 ; number of σ bonds in one molecule of P3 = r
(d) As + conc. HNO₃ → P4 ; number of lone pairs of electrons in P4 = s
Answer:
19
Solution:
(a) Fe²⁺ → Fe³⁺, so p = 3. (b) P2 = BH₃←CO : σ bonds = 3(B-H) + 1(B-C) + 1(C-O) = 5, so q = 5. (c) P3 = C₂H₂ (H-C≡C-H) : 3 σ bonds, so r = 3. (d) P4 = H₃AsO₄ = O=As(OH)₃ : lone pairs = 2 (=O) + 3 × 2 (three -OH) = 8, so s = 8. Sum = 3 + 5 + 3 + 8 = 19.
Stream:JEESubject:ChemistryTopic:Complete P-blockSubtopic:p-Block 15,16
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
