Given that 1.84 gm of IF 3 react with 0.93 gm of [ ( CH 3 ) 4 N ] F to form only product [ X ] , identify [X] and calculate (P) + (Q) + (R)? (Atomic mass of N = 14, C = 12, F = 19, H = 1, I = 12

Question

Given that 1.84 gm of IF 3 ​ react with 0.93 gm of [ ( CH 3 ​ ) 4 ​ N ] F to form only product [ X ] , identify [X] and calculate (P) + (Q) + (R)? (Atomic mass of N = 14, C = 12, F = 19, H = 1, I = 127) P = Maximum number of identical bond length Q = Total number of d-orbital(s) used in hybridisation by atom(s) in [X] R = Total number of 90° bond angle(s)

TestHub · Accepted Answer

Product [X] = [(CH₃)₄N][IF₄]. IF₄⁻ is square planar (sp³d²). P = 12 (12 identical C–H bonds in the cation), Q = 2, R = 4 (four 90° F–I–F angles). Sum = 12 + 2 + 4 = 18.

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