Chemistry - Complete P-block Question with Solution | TestHub

Reducing property of dioxide decreases from ${\mathrm{SO}}_2$ to ${\mathrm{TeO}}_2$

All these elements form oxides of the ${\mathrm{EO}}_2$ and ${\mathrm{EO}}_4$ types

Selenium and tellurium do not form ${\mathrm{SeO}}_3$ and ${\mathrm{TeO}}_3$

${\mathrm{SO}}_2$ is an oxidising agent while ${\mathrm{TeO}}_2$ is a reducing agent.