Chemistry - Complete P-block Question with Solution | TestHub

${\mathrm{PCl}}_5$ when fluorinated in a polar organic solvent, ionic isomers are formed.

When phosphorus pentachloride (${\mathrm{PCl}}_5$) is fluorinated in a polar organic solvent, it undergoes ionization to form ionic species. The fluorination can lead to different products depending on the conditions and the extent of fluorination.

One possible reaction involves the formation of ionic isomers where the ${\mathrm{PCl}}_5$ itself ionizes in the polar solvent, and then fluorination occurs.

${\mathrm{PCl}}_5\rightleftharpoons {\left[{\mathrm{PCl}}_4\right]}^{+}{\left[\mathrm{Cl}\right]}^{-}$

Upon fluorination, the chloride ions can be replaced by fluoride, or the ${\mathrm{PCl}}_5$ can react with a fluorinating agent.

The species formed are typically ionic salts.

One common product is ${\left[{\mathrm{PCl}}_4\right]}^{+}{\left[{\mathrm{PCl}}_4{\mathrm{F}}_2\right]}^{-}$. This indicates that some fluorine atoms have substituted chlorine atoms in the anion.

Another product, especially with stronger fluorinating agents or more extensive fluorination, is ${\left[{\mathrm{PCl}}_4\right]}^{+}{\left[{\mathrm{PF}}_6\right]}^{-}$. Here, the anion is a hexafluorophosphate ion, suggesting a more complete replacement of chlorine by fluorine in the anionic part.

Therefore, both ${\left[{\mathrm{PCl}}_4\right]}^{+}{\left[{\mathrm{PCl}}_4{\mathrm{F}}_2\right]}^{-}$ and ${\left[{\mathrm{PCl}}_4\right]}^{+}{\left[{\mathrm{PF}}_6\right]}^{-}$ are plausible products of fluorination of ${\mathrm{PCl}}_5$ in a polar organic solvent.

The final answer is $\boxed{B}$. $\left[{\mathrm{PCl}}_4^{+}\right]{\left[{\mathrm{PCl}}_4{\mathrm{F}}_2\right]}^{-}$(colorless crystals) $\left[{\mathrm{PCl}}_4^{+}\right]{\left[{\mathrm{PF}}_6\right]}^{-}$(white crystals)