“ A ” obtained by Ostwald's method involving air oxidation of NH 3 , upon further air oxidation produces “ B ”. “ B ” on hydration forms an oxoacid of Nitrogen along with evolution of “ A ”. The

Question

“ A ” obtained by Ostwald's method involving air oxidation of NH 3 , upon further air oxidation produces “ B ”. “ B ” on hydration forms an oxoacid of Nitrogen along with evolution of “ A ”. The oxoacid also produces “ A ” and gives positive brown ring test

TestHub · Accepted Answer

Ostwald's method is based upon catalytic oxidation of ${NH}_{3}$ by atmospheric oxygen.

$4 {NH}_{3} (g) + 5 O_{2} (g) \to_{500 K, 9 bar}^{Pt / Rh gauge catalyst} \underset{(A)}{4 NO (g)} + 6 H_{2} O (g)$

Nitric oxide thus formed combines with oxygen giving ${NO}_{2}$ .

$2 NO (g) + O_{2} (g) \underset{(B)}{⇌ 2 {NO}_{2} (g)}$

Nitrogen dioxide so formed, dissolves in water to give ${HNO}_{3}$ .

$3 {NO}_{2} (g) + H_{2} O (l) \to 2 {HNO}_{3} (aq) + NO (g)$

$∴$ A and B are $NO$ and ${NO}_{2}$ respectively.

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