Chemistry - Complete P-block Question with Solution | TestHub

ChemistryComplete P-blockp-Block 15,16Medium2 minPYQ_2017

ChemistryMediummatching list

The correct sequence of decreasing number of $π$ -bonds in the structure of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is:

Options:

Answer:

Solution:

Number of $π$ -bonds

$H_{2} S_{2} O_{7} = HO - \underset{O}{\overset{O}{\underset{| |}{\overset{| |}{S}}}} - O - \underset{O}{\overset{O}{\underset{| |}{\overset{| |}{S}}}} - OH$ $4$

$H_{2} {So}_{4} = OH - \underset{O}{\overset{O}{\underset{| |}{\overset{| |}{S}}}} - OH$ $2$

$H_{2} {SO}_{3} = HO - \underset{O}{\underset{| |}{\overset{. .}{S}}} - OH$ $1$

Therefore, the correct sequence of decreasing number of pi-bonds is $H_{2} S_{2} O_{7} (4) > H_{2} {SO}_{4} (2) > H_{2} {SO}_{3} (1)$ . The numbers in bracket indicate the number of pi bonds.

Stream:JEESubject:ChemistryTopic:Complete P-blockSubtopic:p-Block 15,16

⏱ 2mℹ️ Source: PYQ_2017

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