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Chemistry - Complete P-block Question with Solution | TestHub

ChemistryComplete P-blockp-Block 15,16Medium2 minPYQ_2013

ChemistryMediumsingle choice

Passage / Comprehension

Paragraph: The reactions of $Cl_{2}$ gas with cold-dilute and hot-concentrated $NaOH$ in water give sodium salts of two (different) oxoacids of chlorine, $P$ and $Q$ , respectively. The $Cl_{2}$ gas reacts with $SO_{2}$ gas, in presence of charcoal, to give a product $R$ . $R$ reacts with white phosphorus to give a compound $S$ . On hydrolysis, $S$ gives an oxoacid of phosphorus, $T$ .

Question: $R, S$ and $T$ , respectively, are

Options:

Answer:

Solution:

${Cl}_{2} + cold dil. NaOH \to NaOCl + NaCl$
${Cl}_{2} + hot conc. NaOH \to {NaClO}_{3} + NaCl$
NaOCl is salt of hypochlorous acid = P.
NaOCl₃is salt of chloric acid = Q.
$\begin{matrix} {Cl}_{2} + {SO}_{2} & \overset{Charcoal}{⟶} & {SO}_{2} {Cl}_{2} (R) \\ {SO}_{2} {Cl}_{2} + P_{4} & ⟶ & {PCl}_{5} (S) + {SO}_{2} \\ {PCl}_{5} + H_{2} O & ⟶ & H_{3} {PO}_{4} (T) + HCl \end{matrix}$

Stream:JEE_ADVSubject:ChemistryTopic:Complete P-blockSubtopic:p-Block 15,16

⏱ 2mℹ️ Source: PYQ_2013

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