Chemistry - Complete d-block Question with Solution | TestHub

In alkaline medium, permanganate ($Mn{O}_4^{-}$) oxidizes iodide ($I^{-}$) to iodate ($I{O}_3^{-}$).

$Mn{O}_4^{-}$ acts as an oxidizing agent, accepting electrons, while $I^{-}$ is oxidized by losing electrons. The balanced reaction is:

$$2Mn{O}_4^{-}+I^{-}+2O{H}^{-}\to 2Mn{O}_4^{2-}+I{O}_3^{-}+H_{2}O$$