′ X ′ + con ⋅ H 2 SO 4 → ′ Z ′ (explosive) Small amount 'Z' may be :

Compound X = K M n O 4 (potassium permanganate). When treated with concentrated H₂SO₄, it forms manganese heptoxide (Mn₂O₇). Reaction: 2 K M n O 4 + H 2 S O 4 → K 2 S O 4 + M n 2 O 7 + H 2 O Mn₂O₇ is a dark green oily liquid and is highly explosive, so it should not be prepared in large amounts. Therefore, the explosive product Z = M n 2 O 7 . Correct Answer: (C) Mn₂O₇

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Chemistry - Complete d-block Question with Solution | TestHub

ChemistryComplete d-blockd-blockMedium2 minQB

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$^{'} X^{'} + con \cdot H_{2} SO_{4} \to^{'} Z^{'}$ (explosive)

Small

amount

'Z' may be :

Options:

Answer:

Solution:

Compound $X = K M n O_{4}$ (potassium permanganate). When treated with concentrated H₂SO₄, it forms manganese heptoxide (Mn₂O₇).

Reaction:

$2 K M n O_{4} + H_{2} S O_{4} \to K_{2} S O_{4} + M n_{2} O_{7} + H_{2} O$

Mn₂O₇ is a dark green oily liquid and is highly explosive, so it should not be prepared in large amounts.

Therefore, the explosive product $Z = M n_{2} O_{7}$ .

Correct Answer: (C) Mn₂O₇

Stream:JEESubject:ChemistryTopic:Complete d-blockSubtopic:d-block

⏱ 2mℹ️ Source: QB

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