Chemistry - Complete d-block Question with Solution | TestHub
List - I | List - II |
|---|---|
(I) | (p) redox reaction |
(II) | (q) one of the products has trigonal planar structure |
(III) | (r) dimeric bridged tetrahedral metal ion |
(IV) | (s) disproportionation |
Options:
Answer:
Solution:
Question Explanation: Matching chemical reactions to their type or a characteristic of their products.
Concept: Types of Chemical Reactions and Structure.
Solution:
(A) O₂⁻ → O₂ + O₂²⁻: Superoxide disproportionates to oxygen and peroxide. The oxygen atom is both oxidized (O.S. -1/2 to 0) and reduced (-1/2 to -1). This is a disproportionation and a redox reaction. (p, s)
(B) CrO₄²⁻ + H⁺ →: Forms the dichromate ion, Cr₂O₇²⁻. This is a dimeric ion with two bridged tetrahedral units. (r)
(C) MnO₄⁻ + NO₂⁻ + H⁺ →: Redox reaction where permanganate is reduced and nitrite is oxidized to nitrate (NO₃⁻). The nitrate ion is trigonal planar. (p, q)
(D) NO₃⁻ + H₂SO₄ + Fe²⁺ →: This is the brown ring test. A redox reaction where nitrate is reduced to NO and Fe²⁺ is oxidized to Fe³⁺, forming the complex . (p)
Disproportionation: An ion is oxidized and reduced simultaneously.
Redox: One compound is oxidized and another is reduced.
A compound having sp² hybridization is trigonal planar, and sp³ is tetrahedral.
Final Answer: A→p,s; B→r; C→p,q; D→p