When ' X ' (purple colour compound) boiled with strong alkaline solution dark green colour compound ( Y ) is formed. Product ( Y ) on addition of H 2 O show disproportionation reaction. Wh

Question

When ' X ' (purple colour compound) boiled with strong alkaline solution dark green colour compound ( Y ) is formed. Product ( Y ) on addition of H 2 ​ O show disproportionation reaction. Which of the following is correct for 'X' & 'Y' ?

TestHub · Accepted Answer

The purple compound 'X' is KMnO₄. When boiled with strong alkaline solution, it forms dark green 'Y', which is K₂MnO₄. The reaction is:

$4 KMnO_{4} + 4 KOH \to 4 K_{2} MnO_{4} + O_{2} + 2 H_{2} O$ .

Thus, O₂ is produced during the formation of Y. K₂MnO₄ disproportionates in water: $3 K_{2} MnO_{4} + 2 H_{2} O \to 2 KMnO_{4} + MnO_{2} + 4 KOH$ .

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