Each of the given reaction produces oxocation / oxoanion of metal CrO 3 + NaOH(aq)⟶ C r O n 1 p Mn 2 O 7 + NaOH(aq) ⟶ M n O n 2 q V 2 O 5 + NaOH(aq) ⟶ V O n 3 r V 2 O 4 + acid(aq) ⟶ V O n

Question

Each of the given reaction produces oxocation / oxoanion of metal

CrO₃ + NaOH(aq)⟶ $C r O_{n_{1}}^{p}$

Mn₂O₇ + NaOH(aq) ⟶ $M n O_{n_{2}}^{q}$

V₂O₅ + NaOH(aq) ⟶ $V O_{n_{3}}^{r}$

V₂O₄ + acid(aq) ⟶ $V O_{n_{4}}^{s}$

n₁, n₂ , n₃ & n₄ are number of oxygen atom(s) and p , q , r & s are charges on that oxocation / oxoanions.

If n₁ + n₂ + n₃+ n₄ = X

and p + q + r + s = Y

Find (X + Y).

TestHub · Accepted Answer

X = 13 Y = − 4

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