Chemistry - Complete d-block Question with Solution | TestHub

Conversion 1 (${Mn{O}_4}^{2-}\to {Mn{O}_4}^{-}$): The manganate ion undergoes disproportionation in an acidic medium like $H_{2}S{O}_4$ to form permanganate, and it can also be directly oxidized by ozone ($O_3$).

Conversion 2 (${Mn}^{2+}\to {Mn{O}_4}^{-}$): In laboratory settings, ${Mn}^{2+}$ is oxidized to purple permanganate using powerful oxidizing agents in acidic media.

Reagent Matching: Acidified sodium bismuthate ($NaBi{O}_3$) and red lead ($P{b}_3{O}_4$) in $HN{O}_3$ serve as these specific laboratory oxidants.

Conclusion: Therefore, options (A) and (B) provide the correct pairs of reagents for the respective conversions.