Chemistry - Complete d-block Question with Solution | TestHub

$\text{Zn}$ has the electronic configuration $[\text{Ar}]3d^{10}4s^2$.

It loses two electrons from the $4s$ orbital to form ${\text{Zn}}^{2+}$ ion, which has a stable completely filled $3d^{10}$ configuration.

Therefore, $\text{Zn}$ exhibits only one oxidation state, which is $+2$.

Other elements like $\text{Mn}$, $\text{Fe}$, and $\text{W}$ exhibit variable oxidation states due to the involvement of both $(n-1)d$ and $ns$ electrons in bond formation.

Answer: $\text{Zn}$