Given below are two statements : Statement (I) : Fusion of MnO 2 with KOH and an oxidising agent gives dark green K 2 MnO 4 . Statement (II) : Manganate ion on electrolytic oxidation in alkaline

Question

Given below are two statements : Statement (I) : Fusion of $MnO_{2}$ with $KOH$ and an oxidising agent gives dark green $K_{2} MnO_{4}$ . Statement (II) : Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion. In the light of the above statements, choose the correct answer from the options given below :

Options:

Answer:

D

Solution:

$MnO_{2} + 4 KOH + O_{2} fused 2 K_{2} MnO_{4} + 2 H_{2} O$ Dark green Electrolytic oxidation in alkaline medium : At anode : $MnO_{4}^{2 -} \to MnO_{4}^{-} + e^{-}$

TestHub · Accepted Answer

MnO 2 ​ + 4 KOH + O 2 ​ fused ​ 2 K 2 ​ MnO 4 ​ + 2 H 2 ​ O Dark green Electrolytic oxidation in alkaline medium : At anode : MnO 4 2 − ​ → MnO 4 − ​ + e −

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Options:

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