Chemistry - Complete d-block Question with Solution | TestHub

In neutral or faintly alkaline solution the oxidation of iodide to iodate taken place with potassium permanganate.

$2{\mathrm{MnO}}_4^{-}+{\mathrm{H}}_2\mathrm{O}+{\mathrm{I}}^{-}\to 2{\mathrm{MnO}}_2+2{\mathrm{OH}}^{-}+{\mathrm{IO}}_3^{-}$In the above reaction ${\mathrm{MnO}}_4^{-}$ is an oxidising agent and ${\mathrm{I}}^{-}$ is a reducing agent. 

Hence option D is the answer.