Chemistry - Complete d-block Question with Solution | TestHub

$3{\mathrm{MnO}}_4^{2-}+4{\mathrm{H}}^{+}⟶2{\mathrm{MnO}}_4^{-}+{\mathrm{MnO}}_2+2{\mathrm{H}}_2\mathrm{O}$

As we can see in this reaction oxidised product of reaction is ${\mathrm{MnO}}_4^{-}$ which has no unpaired electrons. So, magnetic moment will be zero.

$\mathrm{Mn}=$ no. of unpaired electrons is '$0$'

$\mathrm{\mu }=0 \mathrm{B}.\mathrm{M}$