Chemistry - Complete d-block Question with Solution | TestHub

The chemical formula of Prussian blue is$\mathrm{F}{\mathrm{e}}_4\left[\mathrm{F}\mathrm{e}\right(\mathrm{C}\mathrm{N}{)}_6{]}_3$.
$\mathrm{F}{\mathrm{e}}^{3+}$reacts with sodium ferrocyanide to give ferriferrocyanide (Prussian blue) as follows
$4{\text{Fe}}^{3+}+3{\text{Na}}_4[\text{Fe}\left(\text{CN}{)}_6\right]\to \underset{\text{Prussian blue}}{{\text{Fe}}_4{[\text{Fe}{(\text{CN})}_6]}_3}+12{\text{Na}}^{+}$