Chemistry - Complete d-block Question with Solution | TestHub

When neutral or faintly alkaline ${\mathrm{KMnO}}_4$ is treated with potassium iodide, ${\mathrm{KMnO}}_4$ is converted into ${\mathrm{MnO}}_2$ while iodide $\left({\mathrm{I}}^{-}\right)$ion is converted inot ${\mathrm{IO}}_3^{-}$(iodate). The reaction takes place as follows: