Chemistry - Complete d-block Question with Solution | TestHub

$\therefore$ Order of oxidation states is $$\mathrm{Ti}<\mathrm{V}<\mathrm{Cr}<\mathrm{Mn}$$ (b) $\because$ Magnetic moment, $\mu =\sqrt{n(n+2)}$ where, $n=$ no. of unpaired electrons
$\therefore$ Order of magnetic moment is $${\mathrm{Ti}}^{3+}<{\mathrm{V}}^{3+}<{\mathrm{Cr}}^{3+}<{\mathrm{Mn}}^{3+}$$ (c) In 3 -series melting point increases as we move from left to right. But Mn shows low melting point due to its complex formating nature. It is unable to form metallic and covalent bonds. (d)
$\therefore$ Order of second ionisation enthalpy is $$\mathrm{Ti}<\mathrm{V}<\mathrm{Mn}<\mathrm{Cr}$$