Chemistry - Complete d-block Question with Solution | TestHub

ChemistryComplete d-blockd-blockMedium2 minPYQ_2006

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The "spin-only" magnetic moment [in units of Bohr magneton, $(μ_{B})]$ of $Ni^{2 +}$ in aqueous solution would be (Atomic number of $Ni = 28$ )

Answer:

Solution:

Ni²⁺ has 2 unpaired electrons. Spin-only magnetic moment $μ = n (n + 2) = 2 (2 + 2) = 8 \approx 2.83 μ_{B}$ .

Stream:JEESubject:ChemistryTopic:Complete d-blockSubtopic:d-block

⏱ 2mℹ️ Source: PYQ_2006

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