Chemistry - Complete d-block Question with Solution | TestHub

$\begin{array}{ccccccc}\text{ Ion }& \begin{array}{c}\text{ No. of }\\ \text{ Electrons }\end{array}& \begin{array}{c}\text{ Electronic }\\ \text{ Configuration }\end{array}& \text{ Electronic Configuration in box }& \begin{array}{c}\text{ No. of }\\ \text{ Unpaired }\end{array}& \begin{array}{c}\text{ Magnetic }\\ \text{ Nature }\end{array}& \begin{array}{c}\text{ Magnetic Mo- }\\ \text{ ment (BM) }\\ \mu =\sqrt{n(\mathbf{n}+2)}\end{array}\\ {\mathrm{Sc}}^{3+}& 18& [\mathrm{Ar}]3d^{0}4{\mathrm{s}}^0& [\mathrm{Ar}]\begin{array}{lllll}& & & & \end{array}\begin{array}{l}\end{array}& 0& \text{ Diamagnetic }& 0\\ & & & & & & \\ {\mathrm{Ti}}^{3+}& 22& [\mathrm{Ar}]3d^{4}4{\mathrm{s}}^0& [\mathrm{Ar}]\begin{array}{lllll}\uparrow & & & & \end{array}\begin{array}{l}\end{array}& 1& \text{ Paramagnetic }& 1.73\\ & & & & & & \\ {\mathrm{Mn}}^{2+}& 23& [\mathrm{Ar}]3d^{5}4{\mathrm{s}}^0& [\mathrm{Ar}]\begin{array}{lllll}\uparrow & \uparrow & \uparrow & \uparrow & \uparrow \end{array}\begin{array}{l}\end{array}& 5& \text{ Paramagnetic }& 5.92\\ & & & & & & \\ {\mathrm{Fe}}^{2+}& 24& [\mathrm{Ar}]3d^{6}4{\mathrm{s}}^0& [\mathrm{Ar}]\begin{array}{lllll}\uparrow \downarrow & \uparrow & \uparrow & \uparrow & \uparrow \end{array}\begin{array}{l}\end{array}& 4& \text{ Paramagnetic }& 4.9\\ & & & & & & \end{array}$
Related Theory Because of the relatively high forces of attraction among the water molecules due to intermolecular hydrogen bonding, water has $a$ higher surface tension than most other liquids. Related Theory Magnetic properties arise from the spin and orbital angular momentum of the electrons contained in a compound. Compounds are diamagnetic when they contain no unpaired electrons.