Chemistry - CHEMISTRY IN EVERYDAY LIFE Question with Solution | TestHub
ChemistryCHEMISTRY IN EVERYDAY LIFECHEMISTRY IN EVERYDAY LIFEMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The equilibrium pressure of NH4CN(s) NH3(g) + HCN(g) is 3 atm when only NH4CN(s) is taken initially in the first experiment. In the second experiment, NH4CN(s) is allowed to decompose in presence of NH3 in such a way that new partial pressure of NH3 at new equilibrium is equal to total pressure at original equilibrium.
Find the partial pressure of HCN in the second experiment.
Options:
Answer:
C
Solution:
1.5 atm 1.5 atm
Kp= 1.5 × 1.5 = 2.25 atm2
Now new = 3 atm
∴ 1.5 × 1.5 = 3 × PHCN
= PHCN = 0.75 atm
Stream:JEESubject:ChemistryTopic:CHEMISTRY IN EVERYDAY LIFESubtopic:CHEMISTRY IN EVERYDAY LIFE
⏱ 2mℹ️ Source: QB
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