If C (diamond ) → C (graphite ) + X kJ mol − 1 C ( diamond ) + O 2 ( g ) → CO 2 ( g ) + Y kJ mol − 1 C (graphite) + O 2 ( g ) → CO 2 ( g ) + Z kJ mol − 1 at constant temperature. Then

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ChemistryChemical ThermodynamicsGeneral (Work, Energy, Heat, Isothermal, Adiabatic, Isobaric, Isochoric)Medium2 minPYQ_2025

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If $C$ (diamond $) \to C$ (graphite $) + X kJ mol^{- 1}$
$C ($ diamond $) + O_{2} (g) \to CO_{2} (g) + Y kJ mol^{- 1}$
C (graphite) $+ O_{2} (g) \to CO_{2} (g) + Z kJ mol^{- 1}$
at constant temperature. Then

Question diagram: If C (diamond ) → C (graphite ) + X kJ mol − 1 C ( diamond )

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Stream:JEESubject:ChemistryTopic:Chemical ThermodynamicsSubtopic:General (Work, Energy, Heat, Isothermal, Adiabatic, Isobaric, Isochoric)

⏱ 2mℹ️ Source: PYQ_2025

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