Isomerization of gaseous cyclobutene in to gaseous 1,3-butadiene at TK follow first order kinetics. The kinetics of reaction was followed by measuring amount of Bromine consumed at different stages wh

Question

Isomerization of gaseous cyclobutene in to gaseous 1,3-butadiene at TK follow first order kinetics.

The kinetics of reaction was followed by measuring amount of Bromine consumed at different stages which produce 1,2-cyclobutane and 1,2,3,4-tetra bromo butane. Initially pure cyclobutene was taken in a container at TK. The reaction mixture in the container consume 16.0 mL of 1.0 M bromine solution at the end of 20 minutes from the beginning and consume a total of 20 mL of same bromine solution after a very long time. The volume of bromine solution ( in mL ) consumed by reaction mixture in the second container at the end of 40 minutes is

TestHub · Accepted Answer

Initial millimoles of cyclobutene in each container $= 10$

If ' $x$ ' millimoles of cyclobutene isomerize at the end of 20 minutes, the millimoles of bromine consumed $= (10 - x) + 2 x = 16, x = 6 K = \frac{2.303}{20} lo g (\frac{10}{4})$

If ' $y$ ' millimoles of cyclobutene isomerize at the end of 40 minutes, the millimoles of bromine consumed $= (10 - y) + 2 y$

$K = \frac{2.303}{40} lo g (\frac{10}{10 - y})$

By solving, $y = 8.4$

The total volume of bromine solution required $= 18.40 mL$

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