Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsEasy2 minQB

ChemistryEasynumerical

The half-life of a first-order reaction is $60 min$ . What percent of the reactant remains after $180 min$ ?

Answer:

12.50

Solution:

Three half-lives pass, so the fraction remaining is $(1/2)^{3} = 1/8 = 0.125$ . The percentage is $12.50%$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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