Chemistry - Chemical Kinetics Question with Solution | TestHub

For acid catalysed hydrolysis of ester rate law obtained is rate $=\mathrm{k}[$ ester $]\left[{\mathrm{H}}^{+}\right]$, where $\mathrm{k}=0.01{\mathrm{M}}^{-1}{\mathrm{hr}}^{-1}$. What is the half-life (in hours) if the initial concentrations are 0.02 M for the ester and 0.05 M for the catalyzing acid. ( $\ell \mathrm{n}2=0.693$ )