Chemistry - Chemical Kinetics Question with Solution | TestHub

The reversible reaction $\mathrm{S}\rightleftharpoons \mathrm{P}$ is catalysed by a catalyst. The equilibrium constant ${\mathrm{K}}_{\text{eq }}=\frac{[\mathrm{P}]}{[\mathrm{S}]}=2\times 10^3$. The forward rate constant was found to be $5\times 10^4{\mathrm{s}}^{-1}$ and $4\times 10^{-6}{\mathrm{s}}^{-1}$ in the presence and in the absence of the catalyst respectively. If the expected rate constant of backward reaction in the absence of the catalyst is $2\times 10^{-y}{\mathbf{s}}^{-1}$, the value of $\mathbf{y}$ is