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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

ChemistryMediumsingle choice

After two half lives, the number of atoms for a radioactive element would be

where N_o = Initial no. of atoms present.

Options:

Answer:

Solution:

After 'n' half-lives, the remaining atoms are $N = N_{o} (\frac{1}{2})^{n}$ . For two half-lives ( $n = 2$ ), $N = N_{o} (\frac{1}{2})^{2} = (\frac{1}{2 ^{2}}) N_{o}$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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