In the reaction of NO by H 2 it was observed that equimolecular mixture of gases at 500 mm was half changed in 100 seconds. In another experiment with equimolar mixture an initial pressure of 250 mm

Question

In the reaction of NO by H 2 ​ it was observed that equimolecular mixture of gases at 500 mm was half changed in 100 seconds. In another experiment with equimolar mixture an initial pressure of 250 mm , the reaction was half completed in 200 seconds. Calculate the order of reaction.

TestHub · Accepted Answer

Since t 1/2 ​ ∝ a n − 1 1 ​ , So t 2 ​ t 1 ​ ​ = [ a 1 ​ a 2 ​ ​ ] n − 1 = [ p 1 ​ p 2 ​ ​ ] n − 1 . Here p 1 ​ = 500 mm , p 2 ​ = 250 mm , t 1 ​ = 100 sec , t 2 ​ = 200 sec . Thus, 200 100 ​ = [ 500 250 ​ ] n − 1 or n = 2 i.e., the order of reaction = 2 n d .

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