Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical Kineticskinetics of complexreaction Parallel, Reversible, SequentialMedium2 minQB

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For a parallel path

(both of which are second order) the ratio of $\frac{[ B ]}{[ C ]}$ would be

Answer:

Solution:

$\frac{d [ B ]}{d t} = k_{1} [A]^{2}$

$\frac{1}{2} \frac{d [ C ]}{d t} = k_{2} [A]^{2}, \frac{d [ C ]}{d t} = 2 k_{2} [A]^{2}$

$\frac{[ B ]}{[ C ]} = \frac{k _{1}}{2 k _{2}}$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:kinetics of complexreaction Parallel, Reversible, Sequential

⏱ 2mℹ️ Source: QB

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