In a first-order reaction, the concentration of the reactant decreases from 800 mol dm − 3 which is not initial conc. To 50 mol dm − 3 in 2 × 1 0 4 s . The rate constant of the reaction in s − 1 is (

Question

In a first-order reaction, the concentration of the reactant decreases from $800 mol dm^{- 3}$ which is not initial conc. To $50 mol dm^{- 3}$ in $2 \times 1 0^{4} s$ . The rate constant of the reaction in $s^{- 1}$ is ( $lo g 2 = 0.3010$ )

Options:

Answer:

C

Solution:

$k = \frac{2.303}{2 \times 1 0 ^{4}} lo g \frac{800}{50}$

$= 1.386 \times 1 0^{- 4}$

TestHub · Accepted Answer

k = 2 × 1 0 4 2.303 ​ lo g ​ 50 800 ​ = 1.386 × 1 0 − 4

Chemistry - Chemical Kinetics Question with Solution | TestHub

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