Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical Kineticskinetics of complexreaction Parallel, Reversible, SequentialMedium2 minQB

ChemistryMediumsingle choice

In the following parallel reaction,

The percentage of product C formed at any time is

Answer:

Solution:

In the given two parallel first-order reactions,

$\frac{[ B ]}{[ C ]} = \frac{k _{1}}{k _{2}} = \frac{2.50 \times 1 0 ^{- 4}}{12.5 \times 1 0 ^{- 5}}$

$P erce n t a g eo f C = \frac{k _{2} \times 100}{k _{1} + k _{2}} = \frac{1.25 \times 1 0 ^{- 4} \times 100}{3.75 \times 1 0 ^{- 4}} = 33.3%$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:kinetics of complexreaction Parallel, Reversible, Sequential

⏱ 2mℹ️ Source: QB

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