Equal weights of ethane and hydrogen are mixed in an empty container at 2 5 ∘ C . The fraction of total pressure exerted by hydrogen is?

The fraction of total pressure is the mole fraction. Since n = M w , and weights are equal, P H 2 / P t o t a l = ( w / M H 2 ) / ( w / M H 2 + w / M C 2 H 6 ) = 1/2/ ( 1/2 + 1/30 ) = 15/16 .

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ChemistryChemical KineticsMiscellaneous/MixedMedium2 minQB

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Equal weights of ethane and hydrogen are mixed in an empty container at $2 5^{\circ} C$ . The fraction of total pressure exerted by hydrogen is?

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Solution:

The fraction of total pressure is the mole fraction. Since $n = \frac{w}{M}$ , and weights are equal, $P_{H_{2}} / P_{t o t a l} = (w / M_{H_{2}}) / (w / M_{H_{2}} + w / M_{C_{2} H_{6}}) = 1/2/ (1/2 + 1/30) = 15/16$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

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