According to nuclear reaction, 4 Be + 2 4 He → 6 12 C + 0 1 n , the mass number of Be atom is:

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According to nuclear reaction, $_{4} Be +_{2}^{4} He \to_{6}^{12} C +_{0}^{1} n$ , the mass number of Be atom is:

Answer:

Solution:

The law of conservation of mass number applies. Sum of mass numbers on reactant side equals sum on product side.

$X + 4 = 12 + 1 \Rightarrow X = 9$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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