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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsFirst Order ReactionsMedium2 minQB

ChemistryMediumsingle choice

The half life of radioactive polonium is 138.6 days. For ten lakh polonium atoms, the number of disintegrations in 24 hours would be $(lo g 1.005 = 0.0021)$

Options:

Answer:

Solution:

$k t = 2.303 lo g \frac{a}{a - x}$

$a = 1 0^{6}$ , $t = 24$ hrs, and $K = \frac{0.693}{138.6 \times 24} h r^{- 1}$ .

$x$ = number of atoms disintegrated

$\frac{0.693}{138.6 \times 24} \times 24 = 2.303 lo g \frac{1 0 ^{6}}{1 0 ^{6} - x}$

$x = 5000$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:First Order Reactions

⏱ 2mℹ️ Source: QB

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