Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsExperimental determination of order of reactionMedium2 minQB

ChemistryMediumsingle choice

For any reaction $A (g) \to P (s)$ following observation is made :

Time (min): 0, 10, 50

Partial pressure of A (in bar): 16, 8, 4

Order of the reaction may be -

Answer:

Solution:

Pressure falls 16 → 8 in 10 min (first half-life = 10 min). It falls 8 → 4 in the next 40 min (second half-life = 40 min).

$\frac{( t _{1/2} ) _{I}}{( t _{1/2} ) _{II}}$ = $(8/16)^{(n - 1)}$ , so 10/40 = $(1/2)^{(n - 1)}$ = 1/4, giving n - 1 = 2 and n = 3.

Answer: (C).

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Experimental determination of order of reaction

⏱ 2mℹ️ Source: QB

Loading discussions...