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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsArrhenius EquationMedium2 minQB

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If the relation between the rate constants $k_{1}$ and $k_{2}$ of two reactions is $4 k_{1} = k_{2}$ , the relation between the corresponding energies $E_{a_{1}}$ and $E_{a_{2}}$ would be (Assuming frequency factor (A) is same for both reactions)

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Answer:

Solution:

From Arrhenius equation, higher rate constant ( $k$ ) implies lower activation energy ( $E_{a}$ ). Since $k_{2} > k_{1}$ , then $E_{a_{1}} > E_{a_{2}}$ .

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: QB

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