Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsMedium2 minQB

ChemistryMediummultiple choice

For $2^{nd}$ order reaction, which of the following is/are correct?

Answer:

B, C, D

Solution:

$\frac{1}{A _{t}} = \frac{1}{A _{0}} + K t$

For $x %$ completion:

$\frac{1}{100 - x} = \frac{1}{100} + K t_{x} %$

$\frac{100 - ( 100 - x )}{( 100 - x ) 100} = K t_{x} %$

$K t_{x} % = \frac{x}{( 100 - x ) 100}$

For $80%$ completion:

$t_{80%} = \frac{80}{20 \times 100} = \frac{4}{100}$

For $20%$ completion:

$t_{20%} = \frac{20}{80 \times 100} = \frac{1}{400}$

Therefore,

$\frac{t _{80%}}{t _{20%}} = \frac{4/100}{1/400} = \frac{4}{100} \times 400 = 16$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: QB

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