The rate of a reaction gets doubled when the temperature changes from 7 ∘ C to 1 7 ∘ C . By what factor will it change for temperature change from 1 7 ∘ C to 2 7 ∘ C . (Anti lo g 0.281 = 1.909 )

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lo g 2 = − 2.303 R E a ​ ​ [ 280 1 ​ − 290 1 ​ ] E a will constant lo g k 1 ​ k 2 ​ ​ = − 2.303 R E a ​ ​ [ 290 1 ​ − 300 1 ​ ] Let's assuming k 1 ​ k 2 ​ ​ = x . Then, l o g x 0.3010 ​ = 280 × 10 10 × 300 ​ l o g x 0..3010 ​ = 28 30 ​ lo g x = 30 28 × 0.3 ​ lo g ​ x = 0.281 x = 1.91

Chemistry - Chemical Kinetics Question with Solution | TestHub

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