Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsArrhenius EquationMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

From the following data answer the question :

Reaction A + B → P

The energy of activation for reaction $(kcal / mol)$ is $(ln 2 = 0.7)$ :

Answer:

3.36

Solution:

$ln (\frac{r _{2}}{r _{1}}) = \frac{E _{a}}{R} (\frac{1}{T _{1}} - \frac{1}{T _{2}})$

$ln 4 = \frac{E _{a}}{2} [\frac{1}{300} - \frac{1}{400}]$

$E_{a} = 3.36 kcal / mol$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Arrhenius Equation

⏱ 2mℹ️ Source: QB

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