If the rate of a first order reaction is 1.8 × 1 0 − 3 mol L − 1 minute − 1 at the initial concentration 0.3 mol L − 1 . Find the rate constant in terms of second.

Question

TestHub · Accepted Answer

For a first order reaction, the rate equation is given by:

$Rate = k [A]$

Substituting the given values:

$1.8 \times 1 0^{- 3} = k \times 0.3$

$k = \frac{1.8 \times 1 0 ^{- 3}}{0.3} = 6 \times 1 0^{- 3} minute^{- 1}$

To convert the rate constant into seconds, divide by $60$ :

$k = \frac{6 \times 1 0 ^{- 3}}{60} s^{- 1}$

$k = 1 \times 1 0^{- 4} s^{- 1}$

Answer: $1 \times 1 0^{- 4} s^{- 1}$

Chemistry - Chemical Kinetics Question with Solution | TestHub

Options:

Doubts & Discussion