The rate of the reaction 2 A + 3 B → 2 C + D is 6 × 1 0 − 4 mol dm − 3 s − 1 , when [ A ] = [ B ] = 0.3 mol dm − 3 . If the reaction is of first order for A and zeroth order for B, then find the rate

Question

The rate of the reaction 2 A + 3 B → 2 C + D is 6 × 1 0 − 4 mol dm − 3 s − 1 , when [ A ] = [ B ] = 0.3 mol dm − 3 . If the reaction is of first order for A and zeroth order for B, then find the rate constant.

TestHub · Accepted Answer

The rate law for the given reaction is written as:

$Rate = k [A]^{1} [B]^{0}$

Substituting the given values into the rate law equation:

$6 \times 1 0^{- 4} = k (0.3)^{1} (0.3)^{0}$

$6 \times 1 0^{- 4} = k \times 0.3$

$k = \frac{6 \times 1 0 ^{- 4}}{0.3}$

$k = 2 \times 1 0^{- 3} s^{- 1}$

Answer: $2 \times 1 0^{- 3} s^{- 1}$

Chemistry - Chemical Kinetics Question with Solution | TestHub

Options:

Doubts & Discussion