Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsZero Order ReactionsEasy2 minPYQ_2025

ChemistryEasysingle choice

Half life of zero order reaction $A \to$ product is 1 hour, when initial concentration of reaction is $2.0 mol L L^{- 1}$ . The time required to decrease concentration of A from 0.50 to $0.25 mol L^{- 1}$ is:

Options:

Answer:

Solution:

For zero order reaction
$Half life = \frac{A _{o}}{2 k} 60 min = \frac{2}{2 k} k = \frac{1}{60} M / min$
Now
$A_{t} = A_{o} - kt t = \frac{A _{o} - A _{t}}{k} = \frac{0.5 - 0.25}{1/60} 0.25 \times 60$
$t = 15 min$

Stream:JEESubject:ChemistryTopic:Chemical KineticsSubtopic:Zero Order Reactions

⏱ 2mℹ️ Source: PYQ_2025

Doubts & Discussion

Loading discussions...