Chemistry - Chemical Kinetics Question with Solution | TestHub

$\begin{array}{rl}\mathrm{T}& =\frac{\Delta \mathrm{H}}{\Delta \mathrm{S}}\\ \therefore \mathrm{T}& =\frac{-84200\mathrm{J}}{-200\mathrm{J}{\mathrm{K}}^{-1}}=421\mathrm{K}\end{array}$ Since $\Delta H$ and $\Delta S$ are negative, the reaction is spontaneous at low temperatures. Therefore, the highest temperature is $421\mathrm{K}$ and the reaction will proceed in forward direction spontaneously below $421\mathrm{K}$.