Chemistry - Chemical Kinetics Question with Solution | TestHub

Under identical conditions, $\frac{r_1}{r_2}=\sqrt{\frac{{\mathrm{M}}_2}{{\mathrm{M}}_1}}$ As rate of diffusion is also inversely proportional to time, we will have, $\frac{t_2}{t_1}=\sqrt{\frac{\overline{{\mathrm{M}}_2}}{{\mathrm{M}}_1}}$ (A) Thus, For $\mathrm{He},t_2=\sqrt{\frac{4}{2}}(5s)=5\sqrt{2}s\ne 10s$; (B) $\mathrm{For}{\mathrm{O}}_2,t_2=\sqrt{\frac{32}{2}}(5s)=20s$ (C) For $\mathrm{CO},t_2=\sqrt{\frac{28}{2}}(5s)\ne 25s$; (D) For ${\mathrm{CO}}_2,t_2=\sqrt{\frac{44}{2}}(5s)\ne 55s$ #