For first order reaction the concentration of reactant decreases form 0 ⋅ 2 to 0.1 M in 100 minutes. What is the rate constant of the reaction?

(D) k ∴ k = t 1/2 0.693 (For first order reaction) = 100 min 0.693 = 6.93 × 1 0 − 3 min − 1

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsHard2 minPYQ_2020

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For first order reaction the concentration of reactant decreases form $0 \cdot 2$ to $0.1 M$ in 100 minutes. What is the rate constant of the reaction?

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Answer:

Solution:

(D) $k ∴ k = \frac{0.693}{t _{1/2}} (For first order reaction) = \frac{0.693}{100 min} = 6.93 \times 1 0^{- 3} min^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2020

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