Chemistry - Chemical Kinetics Question with Solution | TestHub

${\text{t}}_{\frac{1}{2}}\propto \frac{1}{{\text{C}}_0^{\text{o}\text{r}\text{d}\text{e}\text{r}-1}}$where C₀=initial conc.

^{Now as} ${\text{t}}_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}\propto {\text{C}}_0^{1-\text{o}\text{r}\text{d}\text{e}\text{r}}$

According to the question, half life becomes half on doubling concentration, i.e.,${\mathrm{\text{t}}}_{1/2} \propto {{\mathrm{\text{C}}}_0}^{-1}$

∴ on comparing we get order = 2