Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

A first order reaction with respect to reactant $A$ , has a rate constant $6 {min}^{- 1} .$ If we start with $[A] = 0.5 mol L^{- 1}$ , when would $[A]$ reach the value $0.05 mol L^{- 1}$

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Answer:

Solution:

We know that for first order kinetics
$k = \frac{2.303}{t} l o g \frac{a}{a - x}$
$(a-x) = 0.05 mol L^{- 1}$
$6 = \frac{2.303}{t} l o g \frac{0.5}{0.05}$
or $t = \frac{2.303}{6} log \frac{0.5}{0.05} = \frac{2.303}{6} = 0.384 min$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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