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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

In a reaction carried out at $400 K$ , $0.01 %$ of the total number of collisions is effective. The energy of activation of the reaction is

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Answer:

Solution:

$K = A e^{- \frac{E_{a}}{R T}}$
$e^{\frac{E_{a}}{R T}} = \frac{0.01}{100} \Rightarrow \frac{E_{a}}{R T} = 2.303 \log 10^{- 4}$
$\Rightarrow E_{a} = 2.303 \times 4 \times 400 = 30.6 k J / m o l$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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